Example 3a.2
Given: A lamp weighing W = 10 lb hangs from the ceiling by a steel wire of diameter, D = 0.050 inches.
Req'd: Determine is the stress in the wire.
Sol'n: Stress, s, is the force divided by the area. By statics, the force in the wire is: P = W.
Thus: s = P/A = P/(pD^{2}/4) = (10 lb)/[p(0.05 in.)^{2}/4]
s = 5093 lb/in^{2} = 5100 psi = 5.1 ksi
