Given: An aluminum bar can support a force of P = 42.0 kN in tension before it yields (starts to permanently deform).
Req'd: If the Factor of Safety is 3.00 against yielding, determine the Allowable Load, Pallow (the maximum Working Load), that the bar can be subjected to.
Sol'n:
Pallow = Pf/F.S. = (42.0 kN)/(3.00) = Pallow = 14.0 kN
