Given: An acrylic plastic meter stick has a cross-section of 8 mm by 24 mm, and Young's modulus of 3.1 GPa. Assume the ends are fixed.

Req'd: Determine the critical buckling load P_{cr}.

P_{cr} = N (±1%)

Sol'n: From the Euler Buckling Formula, the critical load for a fixed-fixed column is:

P_{cr} = (p^{2}EI) / (L/2)^{2}

For this case E = 3.1 GPa, L = 1.0 m, and I _{cr}= 24·8^{3}/12 = 1024 mm^{4}

The critical buckling load is then:

P_{cr} = p^{2}(3.1 GPa)(1024 mm^{4}) / (0.5 m)^{2} = P_{cr} = 1270 N